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10 November, 12:14

Prove this identity using the product-to-sum identity for sine:

sin^2x = (1-cos (2x)) / 2

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  1. 10 November, 13:53
    0
    sin x * sin x = 1/2 (cos (x-x) - cos (x+x)) = 1/2 (cos (0) - cos (2x))

    Step-by-step explanation:

    sin² x = sin x * sin x

    using the product-to-sum identity for sine

    sin x * sin x = 1/2 (cos (x-x) - cos (x+x)) = 1/2 (cos (0) - cos (2x))

    cos (0) = 1

    sin² x = (1 - cos (2x)) / 2
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