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16 November, 21:55

Find three consecutive integers such that twice the least integer is 12 more than

the greatest integer.

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Answers (1)
  1. 17 November, 00:32
    0
    14,15, 16 28-12=16 14+2 = 16

    Step-by-step explanation:

    x, x+1 x+2

    2x-12 = x+2

    2x = x+14

    x=14
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