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A parallel system functions whenever at least one of its components works. Consider a parallel system of n components, and suppose that each component works independently with probability 0.5. Find the conditional probability that component 1 works, given that the system is functioning.

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  1. Today, 15:55
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    P (F/W) = 0.5 / (1-0.5^N)

    Step-by-step explanation:

    Since each component is independent of the others then the probability that the system works:

    P (W) = probability that the system works = 1 - probability that the system do not work

    the system will not work only if the N components fail, then

    probability that the system do not work = (1-p) ^N

    where

    p = probability that a component works = 0.5

    thus

    P (W) = 1 - (1-p) ^N = 1 - 0.5^N

    then we can use the theorem of Bayes for conditional probability. Defining the event F = the component 1 works, then

    P (F/W) = P (F∩W) / P (W) = P (F) / P (W) = 0.5 / (1-0.5^N)

    P (F/W) = 0.5 / (1-0.5^N)

    where

    P (F/W) = probability that component 1 works, given that the system is functioning

    P (F∩W) = probability that the component 1 works and system functions = P (F) (if the component 1 works, the system will automatically work)
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