A bullet is fired into the air with an initial velocity of 1800 ft per second, at an angle of 60 degrees from the horizontal. Find the magnitudes of the horizontal and vertical vector components of the velocity vector.

Answer:900 and 1558.8

Step-by-step explanation:

v=velocity=1800 ft

Angle = 60°

The formula to find magnitude of horizontal vector is;

|H. Vector| = v * cos (tita)

|H. Vector| = 1800 * cos (60°)

|H. Vector| = 1800 * 0.5

|H. Vector| = 900

Then vertical vector:

|V. Vector| = v * sin (tita)

|V. Vector| = 1800 * sin (60°)

|V. Vector| = 1800 * 0.8660

|V. Vector| = 1558.8