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10 September, 23:54

The graph of a trigonometric function oscillates between y=1 and y=-7. It reaches its

maximum at x=pi and its minimum at x=3pi. Which of the following could be the equation of the function?

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Answers (1)
  1. 11 September, 03:48
    0
    y = 4 sin (½ x) - 3

    Step-by-step explanation:

    The function is either sine or cosine:

    y = A sin (2π/T x) + C

    y = A cos (2π/T x) + C

    where A is the amplitude, T is the period, and C is the midline.

    The midline is the average of the min and max:

    C = (1 + - 7) / 2

    C = - 3

    The amplitude is half the difference between the min and max:

    A = (1 - - 7) / 2

    A = 4

    The maximum is at x = π, and the minimum is at x = 3π. The difference, 2π, is half the period. So T = 4π.

    Plugging in, the options are:

    y = 4 sin (½ x) - 3

    y = 4 cos (½ x) - 3

    Since the maximum is at x = π, this must be a sine wave.

    y = 4 sin (½ x) - 3
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