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4 November, 02:49

The outcome X of an experiment has only two possible values, X = 4 and X = 5. Given that the expected outcome E (X) = 4.2, find P (X = 5). Give your answer as a decimal.

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  1. 4 November, 04:37
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    P (X=5) = 0.2

    Step-by-step explanation:

    Expected outcome, E (x) = ∑XP (X)

    ∑ = Summation

    X = outcomes

    P (X) = probability of an outcome

    E (X) = (4*P (X=4)) + (5*P (X=5)) = 4.2

    So, 4P (X=4) + 5P (X=5) = 4.2 ... equation 1

    But the sum of probabilities = 1

    That is, P (X=4) + P (X=5) = 1 ... equation 2

    Thus, we have the following system of equations

    4P (X=4) + 5P (X=5) = 4.2 ... equation 1

    P (X=4) + P (X=5) = 1 ... equation 2

    Multiply equation 2 by 4

    4*P (X=4) + 4*P (X=5) = 4*1

    4P (X=4) + 4P (X=5) = 4 ... equation 3

    4P (X=4) + 5P (X=5) = 4.2 ... equation 1

    4P (X=4) + 4P (X=5) = 4 ... equation 3

    Subtract equation 3 from 1

    4P (X=4) - 4P (X=4) + 5P (X=5) - 4P (X=5) = 4.2 - 4

    P (X=5) = 0.2
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