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21 November, 01:08

How do you get 40y from the difference of 2 squares with the problem (5y+4+3x) (5y+4-3x) ? I understand distribution method. I don't know where the 40y comes from using the special product method.

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  1. 21 November, 01:20
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    Step-by-step explanation:

    (5y+4+3x) (5y+4-3x) = (5y+4) ² - (3x) ² ... (from the difference of 2 squares)

    by identity : (a+b) (a-b) = a² - b²

    in this exercice; a = 5y+4 and b = 3x
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