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Mathematics
Brandon Kramer
18 January, 18:25
Calculate y'. xy^4+x^2y=x+3y
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Kirsten Armstrong
18 January, 20:05
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Y^4 + 4xy^3 (y') + 2xy + x^2 (y') = 1 + 3 (y')
(y') (4xy^3 + x^2 - 3) = 1 - y^4 - 2xy
I'll let you do the next line
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