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13 November, 00:19

A bowl contains 4 yellow marbles and 3 red marbles. Eric randomly draws 3 marbles from the bowl. He replaces each marble after it is drawn. What is the probability that he draws 1 yellow marble and 2 red marbles

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  1. 13 November, 00:37
    0
    There are 7 marbles in the bowl all together.

    - - Probability of a yellow marble on any draw = 4/7

    - - Probability of a red marble on any draw = 3/7

    - - Probability of one yellow and two red in 3 draws = (4/7) (3/7) (3/7) = 36/343

    = 10.5% (rounded)
  2. 13 November, 01:15
    0
    First draw p yellow = 4/7

    2nd draw p red = 3/7

    3rd draw p red = 3/7

    To find the probability of this event (1yellow 2 red - with replacement) we multiply the probabilities.

    4/7 x 3/7 x3/7 = 36/343 which cannot be reduced further
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