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20 November, 14:55

The perimeter of a basketball court is 268 feet. The area is 4,200 ft^2. Find the dimension of the court.

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  1. 20 November, 16:06
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    4200 = lw

    268 = 2l+2w

    L = 4200/w

    Plug this into perimeter equation and solve for w. Then solve for l by pluging we into the perimeter eqn
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