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15 June, 11:40

Solve for x. x = log44

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  1. 15 June, 14:06
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    First, set the equation in exponential form.

    x=logbY to b^x=Y

    x=log44. so x=x, b=10, Y=44

    10^x=44

    I know that 10^1=10, 10^2=100, and 10^1.5=31.6 so x should be between 1.5 and 2.

    The answer is x=1.64.
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