Find the solutions to the system:

y = x^2 - 5x + 2

y = - 6x + 4

a. (2, 8) and (-1, 2)

b. (-2, 8) and (1, - 2)

c. (-2, 16) and (1, - 2)

d. no solutions

Y = x² - 5x + 2

y = - 6x + 4

-6x + 4 = x² - 5x + 2

0 = x² - 5x + 2 + 6x - 4

0 = x² + x - 2

(x + 2) (x - 1)

x = - 2; x = 1

y = x² - 5x + 2; x = - 2 y = x² - 5x + 2; x = 1

y = (-2) ² - 5 (-2) + 2 y = 1² - 5 (1) + 2

y = 4 + 10 + 2 y = 1 - 5 + 2

y = 16 y = - 2

y = - 6x + 4; x = - 2 y = - 6x + 4; x = 1

y = - 6 (-2) + 4 y = - 6 (1) + 4

y = 12 + 4 y = - 6 + 4

y = 16 y = - 2

Choice C. (-2, 16) and (1, - 2) is the answer.

The correct answer for the question that is being presented above is this one: "d. no solutions." The solutions to the system is this:d. no solutions

y = x^2 - 5x + 2 (2,8)

y = 4 - 10 + 2

y = 8

y = x^2 - 5x + 2 (-1,2)

y = 1 + 10 + 2

y = 13

y = - 6x + 4 (2,8)

y = - 6 (2) + 4

y = 8

y = - 6x + 4 (-1,2)

y = - 6 (-1) + 4

y = 2