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9 May, 18:29

Find the solutions to the system:

y = x^2 - 5x + 2

y = - 6x + 4

a. (2, 8) and (-1, 2)

b. (-2, 8) and (1, - 2)

c. (-2, 16) and (1, - 2)

d. no solutions

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Answers (2)
  1. 9 May, 18:58
    0
    Y = x² - 5x + 2

    y = - 6x + 4

    -6x + 4 = x² - 5x + 2

    0 = x² - 5x + 2 + 6x - 4

    0 = x² + x - 2

    (x + 2) (x - 1)

    x = - 2; x = 1

    y = x² - 5x + 2; x = - 2 y = x² - 5x + 2; x = 1

    y = (-2) ² - 5 (-2) + 2 y = 1² - 5 (1) + 2

    y = 4 + 10 + 2 y = 1 - 5 + 2

    y = 16 y = - 2

    y = - 6x + 4; x = - 2 y = - 6x + 4; x = 1

    y = - 6 (-2) + 4 y = - 6 (1) + 4

    y = 12 + 4 y = - 6 + 4

    y = 16 y = - 2

    Choice C. (-2, 16) and (1, - 2) is the answer.
  2. 9 May, 19:35
    0
    The correct answer for the question that is being presented above is this one: "d. no solutions." The solutions to the system is this:d. no solutions

    y = x^2 - 5x + 2 (2,8)

    y = 4 - 10 + 2

    y = 8

    y = x^2 - 5x + 2 (-1,2)

    y = 1 + 10 + 2

    y = 13

    y = - 6x + 4 (2,8)

    y = - 6 (2) + 4

    y = 8

    y = - 6x + 4 (-1,2)

    y = - 6 (-1) + 4

    y = 2
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