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22 July, 21:49

Which of the following are solutions to the equation sinx cosx = square root 3/4 check all that apply

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  1. 23 July, 01:37
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    Important to note: sin2x = 2sinxcosx

    Since we know that property, we can divide both sides by 2 to yield: sin2x/2 = sinxcosx

    So, sin2x/2 = sqrt (3) / 4

    sin2x = 2sqrt (3) / 4 = sqrt (3) / 2

    2x = arcsin (sqrt (3) / 2) = 60, 120 in the domain [0, 360]

    x = 30, 60
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