Ask Question
5 November, 08:16

Solve the following equation on the interval [0,2 / pi)

Cot (3x) = / sqrt{3}

+2
Answers (1)
  1. 5 November, 10:52
    0
    Cot (3x) = 3^ (1/2)

    cot (x) = cos (x) / sin (x)

    cot (3x) = cos (3x) / sin (3x)

    look at a unit circle chart

    find a value for cos that has sqrt (3) in it

    which one will reduce so that the cos/sin will equal sqrt (3) ?

    pi/6 radians

    now cot (3x) implies that x is one third this value

    pi/18 is the answer
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Solve the following equation on the interval [0,2 / pi) Cot (3x) = / sqrt{3} ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers