14x^2-17x-6. (^being 14x squared)

Factor?, if so

if in ax^2+bx+c form then

multiply a and c together

result=z,

find 2 numbers that multiply to get z and add up to get b

so

14=a

-17=b

-6=c

14 times - 6=-84

factor to find what 2 numbers add up to - 17

-84=

-2, 42

-3,28

-4,21

-6,14

-7,12

add each up

-2, 42=40 nope

-3,28=25 nope

-4,21=17 yes, becase if - 21 and 4 then answer

-6,14=8 nope

-7,12=5 nope

split up - 17 into - 21 and 4

14x^2-21x+4x-6

group

(14x^2-21x) + (4x-6)

undistribute

(7x) (2x-3) + (2) (2x-3)

revesres undistribute (ab+ac=a (b+c) or (a+b) (c) + (a+b) (d) = (a+b) (c+d))

(7x+2) (3x-3) is factore out form

then set it to zero and do th emath because if xy=0 then assume x and/or y=0 so

7x+2=0

subtract 2

7x=-2

divide by 7

x=-2/7

3x-3=0

add 3

3x=3

divide 3

x=1

x=-2/7 or 1