Two mechanics worked on a car. The first mechanic worked for

20

hours, and the second mechanic worked for

15

hours. Together they charged a total of

$2000

. What was the rate charged per hour by each mechanic if the sum of the two rates was

$115

per hour?

what is the first mechanics $ per hour? and what was the second mechanics $ per hour?

Question

Mathematics

Guest

26 March, 12:37

Two mechanics worked on a car. The first mechanic worked for

20

hours, and the second mechanic worked for

15

hours. Together they charged a total of

$2000

. What was the rate charged per hour by each mechanic if the sum of the two rates was

$115

per hour?

what is the first mechanics $ per hour? and what was the second mechanics $ per hour?

+2

Answers (2)

Know the Answer?

Yair Gill · Answer 1

x=price per hour for first mechanic

y=price per hour for second mechanic

20x+15y=2000

x+y=115

solve

divide first equation by 5

4x+3y=400

multiply second equation by - 3 and add to second

4x+3y=400

-3x-3y=-345 +

1x+0y=55

x=55

x+y=115

55+y=115

minus 55

y=60

first mechanic rage is $55 per hour

second mechanic is $60 per hour

Kayden Mcintyre · Answer 2

20x + 15y = 2000

x + y = 115

55+60=115

20 (55) + 15 (60) = 2000

1100+900=2000

2000=2000