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3 January, 20:06

The area of a rectangular field is x^2-x-72 m^2. The length of the field is x+8 cm. What is the width of the field meters.

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  1. 3 January, 21:26
    0
    Hello,

    A (x) = x²-x-72 (m²)

    L = (x+8) (cm) = (x+8) / 100 (m)

    We suppose here x≠-8

    (in reality x²-x-72>0 = = >x9

    but x+8>0 = = > x>-8

    then

    only x>9 are solutions)

    W=A (x) / ((x+8) / 100) = 100 * (x²-x-72) / (x+8) = 100 * (x-9) (x+8) / (x+8) = 100 * (x-9)
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