Whats the equation of a circle centered at (7,1) that passes through (-2,10)

The line from (7, 1) to (-2 10) is a radius of the circle.

Its length is the square root of [ (-2 - 7) ² + (10 - 1) ² ] = √ (81 + 81) = √162

The equation of the circle is: (x - 7) ² + (y - 1) ² = 162