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16 July, 01:09

Use the quadratic formula to solve 2y2 + 6y - 8 = 0.

A {-4, - 1} B {4, - 1} C {-4, 1} D {4, 1}

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  1. 16 July, 05:01
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    Y = [-6 + / - sqrt (6^2 - 4*2*-8) ] / 2*2

    = (-6 + / - sqrt 100) / 4

    = (-6+10) / 4, (-6-10) / 4

    = (1, - 4)

    the answer is C
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