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2 January, 15:00

What is the growth factor of y=34*4^x, the initial amount of y=15*3^x and the decay factor of y=17*0.2^x

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  1. 2 January, 15:25
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    So the growth factor is the base of the exponential term, so the base of y = 34 * 4^x is 4.

    the initial amount is the amount at x = 0

    y = 15 * 3^xy = 15 * 3^0y = 15 * 1y = 15 is the initial amount

    the decay factor of y=17*0.2^x is same as the growth factor, it is 0.2
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