Can you solve an angle measures 36° more than the measure of a complementary angle. what is the measure of each angle

I'm reading this as ... 36o more then the measure of its complementary angle.

x = 90 - x + 36 add 90 and 36 together.

x = 126 - x Add x to both sides.

2x = 126

x = 126 / 2

x = 63

The complementary angle is 90 - 63 = 27

The question is is 63 36 bigger than 27

27 + 36 = 63 and the angles are

Answer 27o and 63o