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27 December, 05:04

Which operations are the most efficient to use to solve the problem and what is the solution?

The community center just built an outdoor lap pool. The new outdoor pool has an area of 432 square feet and a length of 24 feet. The width of the new outdoor pool is 2 feet longer than the width of the center's indoor pool. What is the width of the community center's indoor pool?

Choose exactly two answers that are correct.

A.

multiplication and subtraction

B.

division and subtraction

C.

16 ft

D.

1,726 ft

+4
Answers (1)
  1. 27 December, 05:26
    0
    Width of outdoor pool = 432 / 24 = 18 ft

    Width of the indoor pool = 18 - 2 = 16 ft

    Therefore, the question is solved by division and multiplication

    and the width of the indoor pool is 16 ft
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