The first three terms of a geometric sequence are shown below. x+3,-2x2-6x, 4x3+12x2, ... What is the eighth term of the sequence?

Geometric sequence is times r each time

a term divideded by the previous term is r

(-2x^2-6x) / (x+3) = - 2x

first term is x+3

an=a1 (r) ^ (n-1)

an = (x+3) (-2x) ^ (r-1)

8th term

an = (x+3) (-2x) ^ (8-1)

an = (x+3) (-2x) ^7

an = (x+3) (-128x^7)

an=-128x^7-384 is the 8th term