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5 April, 23:44

What is the 6th term of the geometric sequence 2/25, 2/5, 2, 10?

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  1. 6 April, 02:23
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    To find the common ratio, divide the second term by the first term.

    (2/5) / (2/25) = 2/5 * 25/2 = 50/10 = 5

    an = a1 * r^ (n-1)

    n = term u want to find = 6

    a1 = first term = 2/25

    r = common ratio = 5

    a6 = 2/25 * 5^ (6-1)

    q6 = 2/25 * 5^5

    a6 = 2/25 * 3125

    a6 = 6250/25

    a6 = 250 <===
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