The length of a rectangle is twice its width. The perimeter is 48 inches. Find the dimensions of the rectangle.

Let us assume the width of the rectangle = x inches

Then

The length of the rectangle = 2x inches

The perimeter of the rectangle as given in the question = 48 inches

We already know

Perimeter of a rectangle = 2 (Length + Width)

48 = 2 (2x + x)

48 = 2 (3x)

48 = 6x

x = 48/6

= 8

So

The width of the rectangle = 8 inches

And

The length of the rectangle = 2x

= 2 * 8 inches

= 16 inches

from the above deduction, we can easily say that the length of the rectangle is 16 inches and the width of the rectangle is 8 inches.