John is 6 years older than Kathy. Together their ages equal four times Kathys age. How old is each?

Question

Mathematics

Kingston Lutz

18 March, 08:12

John is 6 years older than Kathy. Together their ages equal four times Kathys age. How old is each?

+3

Answers (2)

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Tiffany Mccullough · Answer 1

Kathy=k

John=k+6

''Together their ages equal four times Kathys age.''

→k+6+k=4k; 2k+6=4k; 2k=6; k=3

Kathy=3

John=3+6=9

Caiden Church · Answer 2

John is 6 years older the k or Kathy so k+6

together their ages equal four times Kathy's age

so k+6+k=4k 2k+6=4k 6=2k 2k=6 k=3

so john is 9 by 6+3

And Kathy is 3 k=3