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17 April, 17:54

Write an equation in slope intercept form for the line that passes through (-3,2) and is perpendicular to the line described by y=3/2x-4.

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  1. 17 April, 19:35
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    Y = 3/2x - 4 ... slope here is 3/2. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is - 2/3. (see how I flipped the slope and changed the sign)

    y = mx + b

    slope (m) = - 2/3

    (-3,2) ... x = - 3 and y = 2

    now we sub and solve for b, the y int

    2 = - 2/3 (-3) + b

    2 = 2 + b

    2 - 2 = b=0 = b

    so ur perpendicular equation is : y = - 2/3x + 0 or just y = - 2/3x
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