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16 January, 17:12

How many different arrangements could be made using 4 characters if repetition is not allowed? assume your "alphabet" consists of the lower-case letters?

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  1. 16 January, 17:47
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    Assume lower-case English alphabet used.

    first letter: 26 choices

    second letter: 25 choices

    third letter: 24 choices

    fourth letter : 23 choices

    Total number of arrangements = 26*25*24*23=358800
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