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13 November, 10:33

Whatfour consecutive integers have a sum of 90

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  1. 13 November, 11:10
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    N + (n+1) + (n+2) + (n+3) = 90

    if n is the first number, then the next number is 1 more than n, the next number is 2 more than n, etc.

    Simplify the above expression:

    4n + 6 = 90

    4n = 84

    n = 21

    n+1 = 22

    n+2 = 23

    n+3 = 24
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