Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution.

To answer the question above, raise both sides of the equation to the power of two.

(sqrt (2x + 1)) ² = 3²

This will simplify into,

2x + 1 = 9

Solving for the value of x gives an answer of x = 4. This value is not an extraneous root as it satisfy the original equation even if it is inside the radical sign.