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14 April, 16:20

How much work (in joules) is done in moving a charge of 2.5 _C a distance of 53 cm along an equipotential at 10 V? I got - 2.25e-5 is this correct?

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  1. 14 April, 19:19
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    Since the field is equipotential. Thus, change in potential is 0 and thus

    Work = charge x change in potential = 2.5 x 10^-6 x 0 = 0.

    Requires work is 0 joules.
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