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27 November, 21:48

For the function d (x) = 7x^3 - 6x^2 what is the vaule of d (4)

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  1. 27 November, 23:54
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    For this case we have the following function:

    d (x) = 7x ^ 3 - 6x ^ 2

    We evaluate the function for x = 4.

    We have then:

    d (4) = 7 * (4) ^ 3 - 6 * (4) ^ 2

    Rewriting we have:

    d (4) = (4 ^ 2) * (7 * (4) - 6)

    d (4) = 352

    Answer:

    the vaule of d (4) is:

    d (4) = 352
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