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28 April, 22:39

What is the solution set of 6x^2 - 24 = 0?.

A.) {-2, 2}

B.) {-2}

C.) {2}

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Answers (2)
  1. 28 April, 23:10
    0
    If xy=0 then assume taht x and/or y=0

    remember differnce of 2 perfect squares

    a^2-b^2 = (a-b) (a+b)

    factor

    6x^2-24=0

    6 (x^2-4) = 0

    6 (x^2-2^2) = 0

    6 (x-2) (x+2) = 0

    set to zero

    x-2=0

    x=2

    x+2=0

    x=-2

    x=2 and - 2

    A is answer
  2. 29 April, 02:32
    0
    We are given with the expression 6x^2 - 24 = 0. We are asked in the problem for its solution set. The first step to take is to factor out 6 in the equation resulting to x^2 - 4 = 0. This is a special type of equation where after factoring the equation becomes (x-2) * (x+2) = 0. Hence the solution set is A. {-2,2}
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