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27 October, 23:05

What is the tenth term of the geometric sequence that has a common ratio of 1/3 and 36 as its fifth term?

a. 4/7

b. 27/4

c. 4/81

d. 1/36

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Answers (1)
  1. 28 October, 01:44
    0
    To find any term

    of a geometric sequence:

    where a1 is the first term of the sequence,

    r is the common ratio, n is the number of the term to find.

    a5 = a1 * r^4;

    36 = a1 * (1/3) ^4;

    a1 = 36 * 81;

    a1 = 2916;

    a10 = a1 * r^9;

    a10 = 2916 * (1/3) ^9;

    a10 = 2916/13122;

    a10 = 36/243;

    Finally, a10 = 4/27;
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