The sum of two numbers is 44. The larger number is 20 more than the smaller number. What are the numbers?

Let the numebrs be x and y.

x + y = 44

x = y + 20

Substituting the value of x,

(y + 20) + y = 44

2y + 20 = 44

2y = 24

y = 12.

x = y + 20

x = 12 + 20

Thus, x = 32.

Thus, the two numbers are 32 and 12.

The smaller number is 'x'.

The larger number is (x + 20)

Their sum is [ x + (x + 20 ]

2x + 20 = 44

Subtract 20 from each side:

2x = 24

Divide each side by 2:

x = 12

and

x + 20 = 32