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13 January, 07:47

Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.

Write the polynomial function for the graph.

f (x) = (x - 2) (x - 3) (x - 5)

Simplify the right side. What is the equation?

f (x) = x3 + 31x - 30

f (x) = x3 - 10x2 + 31x - 30

f (x) = x3 - 10x2 + 19x - 30

f (x) = x3 + 19x - 30

+2
Answers (2)
  1. 13 January, 08:10
    0
    In others words, it's B
  2. 13 January, 09:46
    0
    F (x) = (x - 2) (x - 3) (x - 5) = x[x (x - 5) - 3 (x - 5) ] - 2[x (x - 5) - 3 (x - 5) ] = x[x^2 - 5x - 3x + 15] - 2[x^2 - 5x - 3x + 15] = x[x^2 - 8x + 15] - 2[x^2 - 8x + 15] = x^3 - 8x^2 + 15x - 2x^2 + 16x - 30 = x^3 - 10x^2 + 31x - 30
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