Eliminate the parameter.

x = t + 4, y = t^2

Choices:

y = square root of x + x + 4

y = square root of quantity x minus four d

y = x^2 + 16

y = x^2 - 8x + 16

Question

Hadassah Macdonald

26 January, 21:45

+2

Answers (1)

Know the Answer?

Fisher Bernard · Answer 1

Hello,

x=t+4==>t=x-4

y=t² = (x-4) ²

==>y=t²-8x+16

Answer D

Eliminate the parameter.x = t + 4, y = t^2Choices:y = square root of x + x + 4y = square root of quantity x minus four dy = x^2 + 16y = x^2 - 8x + 16