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2 June, 10:47

Write an equation of the line through (3,-5) and perpendicular to 3y=x-6

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  1. 2 June, 12:56
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    3y = x - 6

    y = 1/3x - 2.

    slope her is 1/3. A perpendicular line will have anegative reciprocal slope. To find the negative reciprocal of a number, u flip the number and change the sign. So the slope we need os - 3/1 or just - 3. (see how I flipped the slope and changed the sign)

    y = mx + b

    slope (m) = - 3

    (3,-5) ... x = 3 and y = - 5

    now we sub and find b, the y int

    -5 = - 3 (3) + b

    -5 = - 9 + b

    -5 + 9 = b

    4 = b

    so ur perpendicular equation is : y = - 3x + 4
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