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3 January, 15:59

Which function has an axis of symmetry of x = - 2? f (x) = (x - 1) 2 2 f (x) = (x 1) 2 - 2 f (x) = (x - 2) 2 - 1 f (x) = (x 2) 2 - 1

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  1. 3 January, 19:06
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    Ok so the axis of symmery is the x value of the vertex

    remember vertex form

    f (x) = a (x-h) ^2+k

    h is the x value

    so we want

    xvalue=-2=h

    f (x) = a (x - (-2)) ^2+k

    or

    f (x) = a (x+2) ^2+k

    we see that the last one is the answer

    f (x) = (x+2) ^2-1
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