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12 August, 17:56

How to solve 8x^3-27=0

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Answers (2)
  1. 12 August, 19:00
    0
    Factor using difference of cubes, and set each factor equal to 0.

    x = (-3+3i/sqrt (3)) / (4), (-3-3i/sqrt (3)) / (4), (3) / (2)
  2. 12 August, 21:48
    0
    8x³-27=0

    8x³=27

    x³=27/8

    x=∛27/∛8

    x=3/2
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