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18 December, 19:32

Find the approximate surface-area-to-volume ratio of a bowling ball with a radius of 5 inches

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  1. 18 December, 23:28
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    Surface area = 4π (r^2) = 4π (5) ^2

    Volume = [4/3]π (r^3) = [4/3]π (5^3)

    ratio = 4π (5) ^2 / [4/3]π (5^3) = 3/5 = 0.6
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