Suppose a population is known to be normally distributed with a mean, μ, equal to 144 and a standard deviation, σ, equal to 27. Approximately what percent of the population would be between 144 and 171?

Approximately 34%.

Step-by-step explanation:

Calculate the z-scores:

For 144; z = 144 - 144 / 27 = 0

For 172: z = 171-144/27 = 1.

From the Normal distribution table = 0 gives 0.5000 and 1 gives 0.8413.

So required percentage = 0.8413 - 0.5000 = 0.3413.