What are the zeros of the quadratic function F (x) = 6x^2+12x-7

x = - 1 + sqrt (78) / 6

x = - 1 - sqrt (78) / 6

x = - 1 + sqrt (78) / 6

x = - 1 - sqrt (78) / 6

Step-by-step explanation:

Zeros are the x-values where the function is 0

f (x) = 0

6x² + 12x - 7 = 0

a = 6, b = 12, c = - 7

Using Quadratic formula:

x = [-12 + - sqrt (12² - 4 (6) (-7) ]/2 (6)

x = [-12 + - sqrt (312) ]/12

x = [-12 + 2sqrt (78) ]/12

x = - 1 + - sqrt (78) / 6