Ask Question
21 November, 22:13

Have one solution, no solution, or infinitely many solutions

2 (x - 3) = 2x

3 (y - 3) = 2y - 9 + y

10x - 2 - 6x = 3x - 2 + x

4 (x + 3) + 2x = x - 8

+2
Answers (1)
  1. 22 November, 01:40
    0
    2 (x - 3) = 2x

    Cancel 2 on both sides

    x - 3 = x

    Cancel x on both sides

    -3 = 0

    Since - 3 = 0 is false, there is no solution.

    3 (y - 3) = 2y - 9 + y

    Simplify 2y - 9 + y to 3y - 9

    3 (y - 3) = 3y - 9

    Expand

    3y - 9 = 3y - 9

    Since both sides equal, there are infinitely many solutions.

    10x - 2 - 6x = 3x - 2 + x

    Cancel - 2 on both sides

    10x - 6x = 3x + x

    Simplify 10x - 6x to 4x

    4x = 3x + x

    Simplify 3x + x to 4x

    4x = 4x

    Since both sides equal, there are infinitely many solutions.

    4 (x + 3) + 2x = x - 8

    Expand

    4x + 12 + 2x = x - 8

    Simplify 4x + 12 + 2x to 6x + 12

    6x + 12 = x - 8

    Subtract x from both sides

    6x + 12 - x = - 8

    Simplify 6x + 12 - x to 5x + 12

    5x + 12 = - 8

    Subtract 12 from both sides

    5x = - 8 - 12

    Simplify - 8 - 12 to - 20

    5x = - 20

    Divide both sides by 5

    x = - 20/5

    Simplify 20/5 to 4

    x = - 4

    One solution
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Have one solution, no solution, or infinitely many solutions 2 (x - 3) = 2x 3 (y - 3) = 2y - 9 + y 10x - 2 - 6x = 3x - 2 + x 4 (x + 3) + 2x ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers