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12 March, 16:32

What are the vertex and x-intercepts of the graph of y=x^2-4x-21?

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  1. 12 March, 17:13
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    Intercepts at (0,7) and (0,03)

    Vertex at (2,-25)

    Step-by-step explanation:

    Axis of symmetry is - b/2a = - (-4) / 2 (1) = 4/2 = 2 x=2

    Plug x=2 into the equation and get 2^2-4 (2) - 21 = 4-8-21 = - 25

    Vertex is (2,-25)

    Factor the equation (x-7) (x+3)

    Set x-7=0, x=7

    set x+3=0, x = - 3

    x intercepts at 7 and - 3
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