Prove that - -

sec^2ø-tan^2ø=1

Question

Mathematics

Sidney Ramirez

13 May, 20:02

Prove that - -

sec^2ø-tan^2ø=1

+1

Answers (1)

Know the Answer?

Giuliana Santiago · Answer 1

Step-by-step explanation:

We know that sin²Ф+cos²Ф=1

when you divide both sides by cos²Ф you get

sin²Ф/cos²Ф+cos²Ф/cos²Ф=1/cos²²Ф

sin²Ф/cos²Ф=tan²Ф

cos²Ф/cos²Ф=1

1/cos²Ф=sec²Ф

tan²Ф+1=sec²Ф

subtract tan²Ф on both sides

1=sec²Ф-tan²Ф

therefore sec²Ф-tan²Ф=1

Prove that - -sec^2ø-tan^2ø=1

Prove that - -

sec^2ø-tan^2ø=1