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Mathematics
Maddox Gardner
19 February, 21:25
Simplify y^4 (y^3) = y^[1]
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Hutchinson
20 February, 00:25
0
y⁴ · y³ = y¹
y⁷ - y¹ = 0
y (y⁶ - 1) = 0
y = 0, (y⁶ - 1) = 0
y⁶ = 1
|y| = 1
y = (+/-) 1
Answer: y = 0, 1, - 1
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