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19 February, 21:25

Simplify y^4 (y^3) = y^[1]

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  1. 20 February, 00:25
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    y⁴ · y³ = y¹

    y⁷ - y¹ = 0

    y (y⁶ - 1) = 0

    y = 0, (y⁶ - 1) = 0

    y⁶ = 1

    |y| = 1

    y = (+/-) 1

    Answer: y = 0, 1, - 1
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