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Mathematics
Dallas Fisher
10 March, 15:14
Find dy/dx when y=0 if xcosy-sinx-2=0
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Estrella Hess
10 March, 16:41
0
xcos (y) - - > For this part, use the product rule, which would mean
cosy - xsiny * dy/dx
sinx's derivative is just cosx, so we get as a final answer
cosy - xsiny * dy/dx - cosx = 0
-xsiny * dy/dx = cosx - cosy
dy/dx = cosx - cosy / - xsiny
When y=0,
dy/dx = cosx - cosy / - xsiny
dy/dx = cosx - cos (0) / - xsin (0) [note: sin (0) = 0]
dy/dx = undefined [since you can't divide by 0]
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