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8 July, 02:27

The drama club is selling tickets to their play to raise money for the show's expenses. Each student ticket sells for $8 and each adult ticket sells for $12. There was a total of $960 in revenue from the sale of 100 total tickets. Graphically solve a system of equations in order to determine the number of student tickets sold, x, x, and the number of adult tickets sold, y.

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  1. 8 July, 04:09
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    Answer:The no of student ticket, x = 60The no of adult ticket, y = 40

    Step-by-step explanation:

    The drama club is selling tickets to their play to raise money for the show's expenses.

    Let the student ticket be represented as x and adult ticket as y

    Cost of student ticket, x = $8

    Cost of adult ticket, y = $12

    The total number of tickets, x + y = 100 ... (1)

    There was a total of $960 in revenue from the sale of 100 total tickets.

    8x + 12y = 960 ... (2)

    Multiplying eq (1) by 8, we get

    8x + 8y = 800 ... (3)

    Subtract eq (3) from (2), we get

    4y = 160

    y = 40, sub in eq (1)

    x = 60

    The no of student ticket, x = 60

    The no of adult ticket, y = 40
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