The diagonal of a square is 8 units. What is the perimeter of the square?

16√2 or 22.63 units to the nearest hundredth.

Step-by-step explanation:

By Pythagoras the sum of the squares of adjacent sides of the square = 8 squared. So, if the side is x units long, then:

x^2 + x^2 = 8^2

2x^2 = 64

x^2 = 32

x = √32.

So the perimeter = 4√32

= 4*√16*√2

= 16√2.